Question

Solve plzz...

No.spam​

Answer 1

GIVEN :-

Mass = 250 g

Speed = 2 m/s

Time of contact = 10⁻³ sec

The average force exerted by the wall on the ball = ?

━━━━━━━━━━━━━━

$begin{gathered}\begin{gathered}\begin{gathered}:\implies \sf{ \Delta p = mv + mv}\\\\\end{gathered} \end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}:\implies \sf{ \Delta p = 2(mv)}\\\\\end{gathered} \end{gathered}$

Now we shall find the average force!!

$\begin{gathered}\begin{gathered}\begin{gathered}:\implies \sf{F = \dfrac{dp}{dt} }\\\\\end{gathered} \end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}\begin{gathered}:\implies \sf{F = \dfrac{\Delta p}{\Delta t} }\\\\\end{gathered}$

$\begin{gathered}\begin{gathered}:\implies \sf{F = \dfrac{2mv}{\Delta t} }\\\\\end{gathered} \end{gathered}$

$\begin{gathered}\begin{gathered}\begin{gathered}:\implies \sf{F = \dfrac{2 \times 0.25 \times 2}{ {10}^{ - 3}} }\\\\\end{gathered} \end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}:\implies \sf F = \dfrac{2 \times 250 \times 10^{-3} \times 2}{ {10}^{ - 3}} \\\\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}\begin{gathered}:\implies \sf F = \dfrac{1000\times \cancel{10^{-3}}}{\cancel{{10}^{ - 3}}} \\\\\end{gathered} \end{gathered}\end{gathered}$

$:\implies \underline{\boxed{\mathfrak{\pink{ f = 1000 \: n}}}}$