Question

solve plzzz I make you brainlist ​

Answer 1

Answer:

sorry don't know , u can ask from other

Answer 2

Step-by-step explanation:

Hence proved

$x = (3 - 2 \sqrt{2} ) \\ \frac{1}{x } = \frac{1}{3 - 2\sqrt{2} } \\ \frac{1}{3 - 2\sqrt{2} } \times \frac{3 + 2 \sqrt{2} }{3 + 2 \sqrt{2} } \\ \frac{3 + 2 \sqrt{2} }{ {3}^{2} - {2 \sqrt{2} }^{2} } \\ \frac{3 + 2 \sqrt{2} }{9 - 8} \\ \frac{3 + 2 \sqrt{2} }{1} \\ 3 + 2 \sqrt{2} \\ now \: solving \sqrt{x} - \frac{1}{ \sqrt{x} } \\ \sqrt{3 - 2 \sqrt{2} } - \sqrt{3 + 2 \sqrt{2} } \\ \sqrt{2 + 1 - 2 \times 1 \times \sqrt{2} } - \sqrt{2 + 1 + 2 \times 1 \times \sqrt{2} } \\ \sqrt{ ({ \sqrt{2} - 1})^{2} } - \sqrt{( { \sqrt{2} + 1 })^{2} } \\ (\sqrt{2 } - 1) - ( \sqrt{2} + 1) \\ \sqrt{2} - 1 - \sqrt{2} - 1 \\ - 2 \\ \\ \sqrt{x} - \frac{1}{ \sqrt{x} } = - 2$