Question

solve......., plzzzz. ......, fast.......,

Answer 1

here is ur answer hope you like it and

Answer 2

[0010001111]... Hello User... [1001010101]
Here's your answer...

This question... has no solution. No real one.
How? This is how.

We'll first try cross multiplication.
So (x-1)(x-4) = (x-2)(x-3)
x²-5x+4 = x²-5x+6
Which equates to 4=6
Which is obviously not correct.
Next method, we bring all terms to LHS, to make RHS = 0
$\frac{x - 1}{x - 2} - \frac{x - 3}{x - 4} = 0 \\ \frac{ {x}^{2} - 5x + 4 - {x}^{2} + 5x + 6}{(x - 2)(x - 4)} = 0 \\ \frac{10}{(x - 2)(x - 4)} = 0$
Since no fraction having a non-zero numerator can become 0 without the denominator being undefined, it means that (x-2)(x-4) = infinity.
So, there is no solution for this question.

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