Question

## solve plzzzzzz....... ​

Answer 1

GIVEN :-

• A ʙᴜʟʟᴇᴛ ᴏғ ᴍᴀss 20g ɪs ғɪʀᴇᴅ ғʀᴏᴍ ᴀ ʀɪғʟᴇ ᴡɪᴛʜ ᴀ ᴠᴇʟᴏᴄɪᴛʏ ᴏғ 800 m/s .

• Aғᴛᴇʀ ᴘᴀssɪɴɢ ᴛʜʀᴏᴜɢʜ ᴀ ᴍᴜᴅ ᴡᴀʟʟ 100ᴄm ᴛʜɪᴄᴋ, ᴠᴇʟᴏᴄɪᴛʏ ᴅᴇᴏᴘs ᴛᴏ 100 m/s .

TO FIND :-

• Tʜᴇ ᴀᴠᴇʀᴀɢᴇ ʀᴇsɪsᴛᴀɴᴄᴇ ᴏғ ᴛʜᴇ ᴡᴀʟʟ .

SOLUTION :-

• ☯︎ ᴍᴀss ᴏғ ʙᴜʟʟᴇᴛ (m) = 20g = 0.02 kg

• ☯︎ Vᴇʟᴏᴄɪᴛʏ ᴏғ ʙᴜʟʟᴇᴛ ʙᴇғᴏʀᴇ ᴘᴀssɪɴɢ ᴛʜʀᴏᴜɢʜ ᴍᴜᴅ ᴡᴀʟʟ (ᴜ) = 800 m/s

• ☯︎ Vᴇʟᴏᴄɪᴛʏ ᴏғ ʙᴜʟʟᴇᴛ ᴀғᴛᴇʀ ᴘᴀssɪɴɢ ᴛʜʀᴏᴜɢʜ ᴛʜᴇ ᴍᴜᴅ ᴡᴀʟʟ (ᴠ) = 100 m/s

• ☯︎ Dɪsᴛᴀɴᴄᴇ ᴄᴏᴠᴇʀᴇᴅ ʙʏ ʙʏ ᴛʜᴇ ʙᴜʟʟᴇᴛ (s) = 100ᴄm = 1m

ʟᴇᴛ,

ᴀᴠᴇʀᴀɢᴇ ʀᴇsɪsᴛᴀɴᴄᴇ ᴏғғᴇʀᴇᴅ ʙʏ ᴛʜᴇ ᴡᴀʟʟ = $\bf\red{F}$

✯ Aᴄᴄᴏʀᴅɪɴɢ ᴛᴏ ᴡᴏʀᴋ-ᴇɴᴇʀɢʏ ᴛʜᴇᴏʀᴇᴍ,

$\begin{cases} \text{Work done by} \\ \text{resistance offered} \\ \text{by mud wall} \end{cases}\Bigg\} = \begin{cases} \text{Decrease in} \\ \text{kinetic energy}\end{cases}\Bigg\}$

$\huge\red\checkmark$ $\bf\purple{F\:.\:s\:=\:\dfrac{1}{2}\:m\:(u^2\:-\:v^2)\:}$

✯ Nᴏᴡ, ᴀᴠᴇʀᴀɢᴇ ʀᴇsɪsᴛᴀɴᴄᴇ ɪs

$\bf\pink{:\implies\:F\:=\:\dfrac{m\:(u^2\:-\:v^2)}{2\:s}\:}$

$\rm{:\implies\:F\:=\:\dfrac{0.02\:\times\:\Big\{(800)^2\:-\:(100)^2\Big\}}{2\:1}\:}$

$\rm{:\implies\:F\:=\:\dfrac{0.02\times{(640000\:-\:10000)}}{2}\:}$

• $\rm{:\implies\:F\:=\:\dfrac{0.02\times{630000}}{2}\:}$

• $\rm{:\implies\:F\:=\:\dfrac{12600}{2}\:}$

• $\bf\green{:\implies\:F\:=\:6300\:N\:}$

$\huge\red\therefore$ [B] Tʜᴇ ᴀᴠᴇʀᴀɢᴇ ʀᴇsɪsᴛᴀɴᴄᴇ ᴏғ ᴛʜᴇ ᴡᴀʟʟ ɪs "6300 N" .

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Answer 2

Answer:

GIVEN :-

A ʙᴜʟʟᴇᴛ ᴏғ ᴍᴀss 20g ɪs ғɪʀᴇᴅ ғʀᴏᴍ ᴀ ʀɪғʟᴇ ᴡɪᴛʜ ᴀ ᴠᴇʟᴏᴄɪᴛʏ ᴏғ 800 m/s .

Aғᴛᴇʀ ᴘᴀssɪɴɢ ᴛʜʀᴏᴜɢʜ ᴀ ᴍᴜᴅ ᴡᴀʟʟ 100ᴄm ᴛʜɪᴄᴋ, ᴠᴇʟᴏᴄɪᴛʏ ᴅᴇᴏᴘs ᴛᴏ 100 m/s .

TO FIND :-

Tʜᴇ ᴀᴠᴇʀᴀɢᴇ ʀᴇsɪsᴛᴀɴᴄᴇ ᴏғ ᴛʜᴇ ᴡᴀʟʟ .

SOLUTION :-

☯︎ ᴍᴀss ᴏғ ʙᴜʟʟᴇᴛ (m) = 20g = 0.02 kg

☯︎ Vᴇʟᴏᴄɪᴛʏ ᴏғ ʙᴜʟʟᴇᴛ ʙᴇғᴏʀᴇ ᴘᴀssɪɴɢ ᴛʜʀᴏᴜɢʜ ᴍᴜᴅ ᴡᴀʟʟ (ᴜ) = 800 m/s

☯︎ Vᴇʟᴏᴄɪᴛʏ ᴏғ ʙᴜʟʟᴇᴛ ᴀғᴛᴇʀ ᴘᴀssɪɴɢ ᴛʜʀᴏᴜɢʜ ᴛʜᴇ ᴍᴜᴅ ᴡᴀʟʟ (ᴠ) = 100 m/s

☯︎ Dɪsᴛᴀɴᴄᴇ ᴄᴏᴠᴇʀᴇᴅ ʙʏ ʙʏ ᴛʜᴇ ʙᴜʟʟᴇᴛ (s) = 100ᴄm = 1m

ʟᴇᴛ,

ᴀᴠᴇʀᴀɢᴇ ʀᴇsɪsᴛᴀɴᴄᴇ ᴏғғᴇʀᴇᴅ ʙʏ ᴛʜᴇ ᴡᴀʟʟ = $\bf\red{F}$

✯ Aᴄᴄᴏʀᴅɪɴɢ ᴛᴏ ᴡᴏʀᴋ-ᴇɴᴇʀɢʏ ᴛʜᴇᴏʀᴇᴍ,

$\begin{cases} \text{Work done by} \\ \text{resistance offered} \\ \text{by mud wall} \end{cases}\Bigg\} = \begin{cases} \text{Decrease in} \\ \text{kinetic energy}\end{cases}\Bigg\}$

$\huge\red\checkmark$ $\bf\purple{F\:.\:s\:=\:\dfrac{1}{2}\:m\:(u^2\:-\:v^2)\:}$

✯ Nᴏᴡ, ᴀᴠᴇʀᴀɢᴇ ʀᴇsɪsᴛᴀɴᴄᴇ ɪs

$\bf\pink{:\implies\:F\:=\:\dfrac{m\:(u^2\:-\:v^2)}{2\:s}\:}$

$\rm{:\implies\:F\:=\:\dfrac{0.02\:\times\:\Big\{(800)^2\:-\:(100)^2\Big\}}{2\:1}\:}$

$\rm{:\implies\:F\:=\:\dfrac{0.02\times{(640000\:-\:10000)}}{2}\:}$

$\rm{:\implies\:F\:=\:\dfrac{0.02\times{630000}}{2}\:}$

$\rm{:\implies\:F\:=\:\dfrac{12600}{2}\:}$

$\bf\green{:\implies\:F\:=\:6300\:N\:}$

$\huge\red\therefore$ [B] Tʜᴇ ᴀᴠᴇʀᴀɢᴇ ʀᴇsɪsᴛᴀɴᴄᴇ ᴏғ ᴛʜᴇ ᴡᴀʟʟ ɪs "6300 N" .

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