Question

solve plzzzzzzz ??? ​

Answer 1

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Answer:-

$\red{\bigstar}$ The 3rd number in sequence will be $\large\leadsto{\sf\green{23}}$

• Given:-

Sum of 3 consecutive integers = 66

• To Find:-

3rd number in the sequence = ?

• Solution:-

Let the 3 consecutive numbers be x, x+1, x+2.

ACCORDING TO QUESTION:-

$\implies\sf{x + (x+1) + (x+2) = 66}$

$\implies\sf{3x + 3 = 66}$

$\implies\sf{3(x+1) = 66}$

$\implies\sf{x+1 = \dfrac{66}{3}}$

$\implies\sf{x+1 = 22}$

$\implies\sf{x = 22 - 1}$

$\implies\bf\red{x = 21}$

Hence, the 3 numbers are:-

$\orange{\bigstar}$ x = 21

$\blue{\bigstar}$ x+1 = 21 + 1 → 22

$\green{\bigstar}$ x+2 = 21 + 2 → 23

—:: Therefore, the 3rd number in the. sequence will be $\large\bf\red{23}$

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Answer 2

$\huge\bold{\gray{\sf{Answer:}}}$

Explanation:

Given :

The sum of 3 consecutive integers is 66

To Find :

Third number in this sequence..??

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Let the first number be 'x'

Second number be 'x+1'

Third number be 'x+2'

Now, according to Question :-

➠x+(x+1)+(x+2)=66

➠3x+3=66

➠3x=63

➠x=63/3=21

$\bold{∴\: the\: first \:number \:is \:{\orange{21}}}$

$\bold{Second\: number\: will\: be \:x+1=21+1={\pink{22}}}$

$\bold{Third \:number\: is\: x+2=21+2={\red{23}}}$

The Third number in this sequence is $\huge\bold{\red{23}}$

Now check:-

$21 + 22 + 23 = 63$