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Answered by
60
The required answer is 2.
A logarithm is given to us.
The logarithm is ![\sf{log_{8}^{\sqrt{4096}}} \sf{log_{8}^{\sqrt{4096}}}](https://tex.z-dn.net/?f=%5Csf%7Blog_%7B8%7D%5E%7B%5Csqrt%7B4096%7D%7D%7D)
The value of the given logarithm.
Taking the given logarithm ,
=
=
=
=
=
=
=
Hence the required answer is 2.
There are two systems of logarithm ,
Natural logarithm
Common logarithm
These were introduced by Napier. They are calculated to the base e (Euler's number) , whose value is approximately equal to 2.7828. These are used in higher mathematics .
The logarithms to the base 10 are called Common logarithms . This was introduced by Briggs , who was contemporary of Napier .
Logs are defined for positive bases only. (except 1).
It is defined for positive real numbers.
Answered by
53
Answer:
Formula:
logb(x) = y, if by = x
Input:
x = 4096
b = 8
y = log₈4096
= log₈ 8⁴
= 4 log₈8 = 4 x 1
log₈4096 = 4
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