Math, asked by fof48, 4 months ago

solve plzzzzzzzz.. ​

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Answered by BrainlyEmpire
60

\large{\underline{\underline{\red{\bf{Answer:}}}}}

The required answer is 2.

\rule{200}4

\large{\underline{\underline{\red{\bf{Step\:by\:step\: explanation:}}}}}

{\underline{\underline{\purple{\bf{Given:}}}}}

A logarithm is given to us.

The logarithm is \sf{log_{8}^{\sqrt{4096}}}

{\underline{\underline{\purple{\bf{To\: Find:}}}}}

The value of the given logarithm.

{\underline{\underline{\purple{\bf{Answer:}}}}}

Taking the given logarithm ,

= \sf{log_{8}^{\sqrt{4096}}}

= \sf{ log_{8}^{\sqrt{64\times 64}}}

=  \sf{log _{8} ^{64}}

= \sf{log _{8} ^{8^2}}

= \sf{2\times log_{8}^{8}}

= \sf{2\times1}

=\bf{2}

Hence the required answer is 2.

\rule{200}2

{\underline{\underline{\purple{\bf{Some\:more\: information:}}}}}

There are two systems of logarithm ,

Natural logarithm

Common logarithm

{\orange{\bf{\leadsto Natural \: logarithms:}}}

These were introduced by Napier. They are calculated to the base e (Euler's number) , whose value is approximately equal to 2.7828. These are used in higher mathematics .

{\orange{\bf{\leadsto Common \: logarithms:}}}

The logarithms to the base 10 are called Common logarithms . This was introduced by Briggs , who was contemporary of Napier .

{\underline{\underline{\purple{\bf{\longmapsto Properties\:of\: logarithms:}}}}}

Logs are defined for positive bases only. (except 1).

It is defined for positive real numbers.

Answered by Anonymous
53

Answer:

Formula:

logb(x) = y, if by = x

Input:

x = 4096

b = 8

  \mathbb\orange{SOLUTION}

y = log₈4096

= log₈ 8⁴

= 4 log₈8 = 4 x 1

log₈4096 = 4

  \huge\mathfrak  \pink{hope \: this \: helps \: u}

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