solve plzzzzzzzz frnds
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Since LBAC + LACB + LABC= 180 degree (sum of all angles of a triangle)
35+65+LBAC = 180
LBAC = 180-100
= 80 degree
Since BC is the bisector of LBAC
LBAX=LCAX
LBAX+LCAX=LBAC
2LBAX= 80
LBAX = 40 degree
Therefore LBAX = LCAX = 40 degree
Since 40>35
BX>AX.- - - - 1
(Side apposite greater angle is greater)
Since 65>40
AX>CX- - - - 2
(Side opposite greater angle is greater)
From 1&2 we can say that
BX>AX>CX
Hope this helps you
35+65+LBAC = 180
LBAC = 180-100
= 80 degree
Since BC is the bisector of LBAC
LBAX=LCAX
LBAX+LCAX=LBAC
2LBAX= 80
LBAX = 40 degree
Therefore LBAX = LCAX = 40 degree
Since 40>35
BX>AX.- - - - 1
(Side apposite greater angle is greater)
Since 65>40
AX>CX- - - - 2
(Side opposite greater angle is greater)
From 1&2 we can say that
BX>AX>CX
Hope this helps you
pritibhamra94pb4for:
thank you
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