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Answer:40 Ohm
Explanation:
Let length of thicker wire be L1 and that of other be L2.
Also given that, A1:A2=3:1
Or, A1=3A2
Since length is same for both wires, L1=L2
R1={(Rho)L1/A1}=10 Ohm
And R2={(Rho)L2/A2}
For series equivalent, total resistance is
R (equivalent)=R1+R2
={rho*L1/A1}+{rho*L1/A2}
={rho*L1/A1}+{rho*L1/(A1/3)}
=(10+3×10)
=40 Ohm
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