Question

Solve previous year Question of iit jee
chapter :- magnetic effect of current​

Answer 1

✯ $\pink{\bold{Refer\;The\; Attachment}}$

• $\sf{Option\;B. \;- \;}{\red{\bold{n²B}}}$

$\boxed{\tt{@MrSovereign}}$

Hope This Helps!!

Answer 2

Explanation:

Given :- The magnetic field at the the centre of the loop is "B"

It is then bent into a circular loop of " n " turns .

The magnetic field at the the centre of circular coil is , B = μ₀I/2r

Where, r = radius of circle = L/2π [ ∵ L = 2πr]

∴ B = μ₀ I/2 × 2π /L = μ₀Iπ/L _____(i)

When wire of length " L" bents into s circular loops of "n" terms, Then

• L = n × 2πr'

• r' = L / n× 2π

• Thus, New magnetic field ,

• B ' = μ₀nI / 2r' = μ₀nI /2 × n×2π /L

• = μ₀ I π /L × n² From _____(i)

• B' = μ₀Iπ/L × n² Answer