Question

Solve previous year Question of iit jee

Chapter :- sequence and series​

Answer 1

Answer:

Option (c) , α-β/100 is the common diffrence of the given A.P

Step-by-step explanation:

Given:- a₂+a₄ + a₆ +-----------+ a₂₀₀ = α_____(1)

and, a₁ + + a₃ + a₅ + -----------a₁₉₉ = β ______(2)

On substracting Eq . (ii) from eq. (i) , we get,

(a₂ - a₁ )+ (a₄- a₃) + (a₆ - a₅ ) +----------(a₂₀₀ - a ₁₉₉) = α - β

• =>d + d + d -------100times = α - β

• => 100d = α - β

• => d = α - β /100 Answer