Question

solve (px-y)(py+x)=h^2p

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Answer 1

Simplifying

(px + -1y)(py + x) = h2p

Multiply (px + -1y) * (py + x)

(px(py + x) + -1y * (py + x)) = h2p

((py * px + x * px) + -1y * (py + x)) = h2p

Reorder the terms:

((px2 + p2xy) + -1y * (py + x)) = h2p

((px2 + p2xy) + -1y * (py + x)) = h2p

(px2 + p2xy + (py * -1y + x * -1y)) = h2p

(px2 + p2xy + (-1py2 + -1xy)) = h2p

Reorder the terms:

(px2 + -1py2 + p2xy + -1xy) = h2p

(px2 + -1py2 + p2xy + -1xy) = h2p

Solving

px2 + -1py2 + p2xy + -1xy = h2p

Solving for variable 'p'.

Reorder the terms:

-1h2p + px2 + -1py2 + p2xy + -1xy = h2p + -1h2p

Combine like terms: h2p + -1h2p = 0

-1h2p + px2 + -1py2 + p2xy + -1xy = 0

The solution to this equation could not be determined