solve Q. 1 b part...........
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First=
InΔACD and ΔACB
AD=AB(given)
<DAC=<BAC(given)
AC=AC(common side)
ΔACD~ΔACB(bySAS criteria)
Similarly,
ΔCAO~BDO(SAS CRITERIA)
InΔACD and ΔACB
AD=AB(given)
<DAC=<BAC(given)
AC=AC(common side)
ΔACD~ΔACB(bySAS criteria)
Similarly,
ΔCAO~BDO(SAS CRITERIA)
Answered by
3
Heya mate,Here is ur answer
b) Given:OC=OD
AO=OB
To Prove:∆AOC=∆BOD
Proof:OC=OD(Given)
AO=OB(given)
Angle AOC=angle BOD(Vertically opposite angles)
So,∆AOC=~ ∆BOD(By SAS congruence criterion)
Warm regards
@Laughterqueen
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b) Given:OC=OD
AO=OB
To Prove:∆AOC=∆BOD
Proof:OC=OD(Given)
AO=OB(given)
Angle AOC=angle BOD(Vertically opposite angles)
So,∆AOC=~ ∆BOD(By SAS congruence criterion)
Warm regards
@Laughterqueen
◦•●◉✿[Tʜᴀɴᴋ ʏᴏᴜ]✿◉●•◦
●▬▬▬▬▬ஜ۩۞۩ஜ▬▬▬▬▬▬●
Be Brainly ✌✌✌
sharukhkhan56:
thanku
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