Math, asked by arnesh1, 10 months ago

solve Q.11 a). Just checking if I did correct in exam. Congruency Chapter

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Answered by emma3006

2

In ∆OAP & ∆OBQ

PA = QB (given)

<PAO = < QBO (both equal to 90°)

<POA = <QOB (vertically opposite angles)

∆OAP≈ ∆OBQ (by AAS congruency criteria)

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