solve q 11 please fast
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1424, 2096, 1844 these three numbers give remainder 10
that means if we subtract 10 from all of them then we will get the number that will be completely divisible by 10
so , (1424 - 10) = 1414
(2096 - 10) = 2086
(1844 - 10) = 1834
Now take the HCF of 1414, 2086 and 1834
1414 = 7x2x101
2086 = 7x2x149
1834 = 7x2x131
HCF = 7x2 = 14
So N will be 14
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