Question

solve q-19.....plzz


.......

Answer 1

Hey friend

by using discriminant formula

A/c to question it has real and equal both roots
so ,

D=(2b)²-4ac= > 0

4{b²-ac}= >0

b²=ac

so ..here as b² = > ac

and again ..in 2 nd equation ...

bx²-2√acx+b= > 0

where a =b
b=2√ac

c=b

now..by using discriminant formula .

D=4ac-4b²= > 0

4{ac-b²}= > 0

ac-b²= >0

b²=ac

hope it helps you.

@Rajukumar 111

Answer 2

I hope , I do help you