Question

solve q. 3.................

Answer 1

Method of Solution:

[We know that Area of Triangle = 1/2×base× Height]

Given: Altitude of Triangle = 11 Metres

Area of Triangle = 220m²

To Find = Base of Triangle

Area of Triangle = 1/2×base× Altitude

220m² ×2 = Base ×11

440m²=11(m)Base

•°• Base = 440m²/11m

Base = 40 metre

Then, Required Value of Base of Triangle is 40 metre.

Answer 2

$Hey\:!!..$

The answer goes here....

_______________________________________

》To find -

Length of base.

》Given -

Area of triangle = $220\:{m}^{2}$

Attitude = 11 m

》Solution -

Let the base of the triangle be $x$

Now, we know that :

Area of triangle = $\frac{1}{2}$ × base × attitude

⇒ 220 = $\frac{1}{2}$ × $x$ × 11

⇒ 220 × 2 = 11 × $x$

⇒ 440 ${m}^{2}$ = 11 × $x$

⇒ $x$ = 40 m

So, the base of the triangle is 40 m.

_______________________________________

Thanks !!..