solve Q.3 plz fast as possible
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1
Answer:
Step-by-step explanation:
InΔABE AND Δ CDB
∠A=∠C
EB=DB
AE=BC
∴ΔABE≅ΔCDB(SAS CRITERION)
Rufus2003:
PLEASE MARK AS BRAINLIEST
Answered by
0
Answer:
Step-by-step explanation:
given: EB=DB , AE=BC, angle A= angle C= 90 degrees to prove: triangle ABE is congruent to triangle CDB proof: in Δ ABE AND Δ CDB AE=BC given
∠a=∠c each90
EB=DB given
therefore Δ ABE≅ΔCDB
so, ∠ABE=∠CDB (CPCT)
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