Math, asked by Anonymous, 1 year ago

solve q.50 plz
answer is 2

Plz provide details

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Answers

Answered by Anonymous
9

ur answer is in attachment

be happy

be brainly :)

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Anonymous: thanks
Answered by Shubhendu8898
6

Given,

 cosec^{2}A.sec^{2}B - cosec^{2}A.tan^{2}B - cot^{2}A.sec^{2}A  + cot^{2}A.tan^{2}B+ cosec^{6} - cot^{6} + -3cosec^{2}A. cot^{2}A \\ \\ =  cosec^{2}A(sec^{2}B -tan^{2}B)  - cot^{2}A(-tan^{2}B  + sec^{2}B) + (cosec^{2}A)^{3} - (cot^{2}A)^{3} - 3cosec^{2}A.cot^{2}A \\ \\ = cosec^{2}A*1 -  cot^{2}A*1 + (cosec^{2}A - cot^{2}A)(cosec^{4} + cot^{4} +2cosec^{2}A.cot^{2}A) -3cosec^{2}A.cot^{2}A \\ \\ = cosec^{2}A - cot^{2}A  + 1*[ (cosec^{2}A-cot^{2}A)^{2} + 3cosec^{2}A.cot^{2}A) - 3cosec^{2}A.cot^{2}A]  \\ \\   = 1 + [1 + 3cosec^{2}A.cot^{2}A} ] -3cosec^{2}A.cot^{2}B \\ \\ = 2  \ \textbf{Ans.}


Anonymous: nice answer
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