Solve q. no. 7 please
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xXTheLegendarySamXx:
look let me explain this
there are two parts in calculas
1 differentiation 2 integration
if we differentiate above equation
Try it n
you will get only dy/dx instead of dv/dt which is the formula of acceleration
then here i go
OK try it plz
Whr is the ans
as you wish the answer has been given..... check that out
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we have,
v = √(180-16x)m/s
let the taken time is t.
now,
on differentiating both sides w.r.t. t , we get
dv/dt= d/dt √(180-16x)
= 1/2√(180-16x).(-16dx/dt)
= -8√(180-16x)dx/dt
answer is -8 √(180-16)dx /dt
note:
da/dx = 0
dx/dx=1
af(x)/dx= ad(f(x))/dx
v = √(180-16x)m/s
let the taken time is t.
now,
on differentiating both sides w.r.t. t , we get
dv/dt= d/dt √(180-16x)
= 1/2√(180-16x).(-16dx/dt)
= -8√(180-16x)dx/dt
answer is -8 √(180-16)dx /dt
note:
da/dx = 0
dx/dx=1
af(x)/dx= ad(f(x))/dx
if the time is given the answer may differ
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