Math, asked by swarajmax26, 9 months ago

Solve q4.
For me if not visible then tell me

Attachments:

Answers

Answered by AdorableMe
1

(sin²22°+sin²68°/cos²22°+cos²68°)+sin63°+cos63°*cos27°

=[sin²(90°-68°)+sin²68°/cos²(90°-68°)+cos²68°]+sin63°+cos(90°-27°)*sin27°

=cos²68°+sin²68°/sin²68°+cos²68° + sin63°+sin27°*sin27°

=1/1+sin63°+sin27°*sin27°

=sin63°+sin27°*cos27°

=sin63°+sin²27°

I think the question is a bit incomplete.

But if it is correct, then this is ur answer.

Similar questions