Question

solve q4 in attachment..

Answer 1

HEY MATE

your answer is in attachment

Answer 2

Answer:

8 cm

Step-by-step explanation:

$\text{Height of cone = 9 cm}\\\\\text{Let its radius be r cm}\\\\\text{Now, volume of cone = } \dfrac{1}{3} \pi r^2 h\\\\\\= \dfrac{22 \times 9}{7 \times 3} \times r^2\\\\\\= \dfrac{198}{21} r^2\\\\\\\text{But, given volume = 48} \pi \: cm^3\\\\\text{Thus,  According to question,}\\\\\dfrac{198}{21} \times r^2 = 48 \times \dfrac{22}{7}\\\\\\\implies r^2 = \dfrac{48 \times 22 \times 21}{7 \times 198} = 16\\\\\\\implies r = \sqrt{16} = \boxed{4}$

Since, Diameter = 2 * Radius, D = 2*4 = 8 cm.