Question

solve q6..help plzzz​

Answer 1

AC||DE ..... given

Thus, angle ABE = angle E

32°+x=122°

So, x =90°

angle BDE=180°-y

,and angle BED =180°-122°=58° ......linear pairs

Therefore, x+180°-y+58°=180° ...angle sum property

90°+180°+58°-y=180°

...subtracting 180° from both sides

148°-y=0

Thus, y=148°

Hope it helps

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Answer 2

Answer:

x=90 and y= 148

hope it helps dear

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