Solve Q7 please please please don't scam me
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let 1/x+y=u and 1/x-y be v
so 10u+2v=4
2(5u+v)=4
5u+v=2. _(1)
15u-5v =-2 _(2)
so
so 10u+2v=4
2(5u+v)=4
5u+v=2. _(1)
15u-5v =-2 _(2)
so
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ANSWER:
Let 1/x+y be u
Let 1/x-y be v
Therefore,
10u + 2v = 4 .... eq 1
Multiply whole by 5
50u + 10v = 20
15u - 5v = -2 .... eq 2
Multiply whole by 2
30u - 10v = -4
50u + 10v=20 ( elimination method)
30u -10v =-4
________________
80u = 16
U = 0.2
Putting value of u in eq2
15 * 0.2 - 5v = -2
-5v = -2 -3
-5v = -5
V = 1
Therefore,
1/x+y = u. 1/x-y = v
X+y = 5 X-y = 1
X= 1+y
Putting value of x
X+y = 5
1+ y +y = 5
2y = 5-1
Y= 2
Putting value of y in other eq
X = 1+y
X= 3
Therefore,
X=3
Y=2
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