Question

solve Q9 with explanation.​

Answer 1

4) 6.125 g/l

mEq of H₂So₄ = mEq of NaOH

( mEq= N × V in ml)

N × 12 = 1/10 × 15

normality of NaOH solution = 15/ 10×12

= 0.125

Strength of H₂SO₄ = normality × Eq.wt.

= 49×0.125

= 6.125 g/l

Strength of H₂SO₄ is 6.125 g/l