Question

Solve quadratc equation: 10x^2-3x+5=0

Answer 1

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Answer 2

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Here is your answer.

The quadratic equation is
$10 {x}^{2} - 3x + 5 = 0$
Here
a= 10
b = -3
c = 5
Now
D =
$= {b}^{2} - 4ac \\ = {( - 3)}^{2} - 4 \times 10 \times 5 \\ = 9 - 200 \\ = - 191$
Therefore this equation has no real roots
Roots are ,=( -b+√D)/2a
=( -(-3)+√-191)/2×10
and
(3-√-191)/20

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