Question

solve quadratic equation 1/7(3x+5)^2=28​

Answer 1

Answer:

your answer would be √7/3.

hope this helps you.

Step-by-step explanation:

1/7(3x + 5)^2=28

1/7(9x^2 + 25) =28

9x^2 +25 = 28/7

9x^2 = 4 - 25

9x^2= 21

x^2=21/9

x = √7/3

Thank you.

Answer 2

Answer:

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