Question

solve quadratic equation 2x²+4x+6=0​

Answer 1

Answer:

$2 {x}^{2} + 4x - 6 = 0$

$2( {x}^{2} + 2x - 3) = 0$

${x}^{2} + 2x - 3 = 0$

${x}^{2} + 3x - x - 3 = 0$

$x(x + 3) - 1(x + 3) = 0$

$(x + 3)(x - 1) = 0$

$if \: (x + 3) = 0 \\ x = - 3$

$if \: x - 1 =0 \\ x = 1$

Answer 2

Answer:

see the attached picture.

Step-by-step explanation:

#hope it's helpful

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