Question

Solve quadratic equation 2x2-x+1/8 = 0
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Answer 1

$\small\bold{Given \: equation \: is \: 2x^2-x+ \frac{1}{8} = 0}$

$\bold{16x^2−8x+1=0}$

$\bold{16x^2 −4x−4x+1=0}$

$\bold{4x(4x−1)−1(4x−1)=0}$

$\bold{(4x−1)^2=0}$

$\bold{x = \frac{1}{4} \: and \: x = \frac{1}{4}}$

Answer 2

Answer:

2x²-x+[1/8]=0

multiply the equation by 8

8(2x²)-8x+[1/8]8=0

16x²-8x+1=0

2x(8x+1)-1(8x+1)=0

(8x+1)or(2x-1)=0

(8x+1)=0

x=-1/8

or

(2x-1)=0

x=1/2