Question

solve quadratic equation
3x-2/2x-3 = 3x-8/x+4​

Answer 1

3x-2/2x-3 = 3x-8/x+4

3x-2(x+4)=2x-3(3x-8)

3x(x+4)-2(x+4)=2x(3x-8)-3(3x-8)

3x²+12x-2x-8=6x²-16x-9x+24

3x²+10x-8=6x²-25x+24

3x²-6x²+19x+25x=-8+24

-3x²+44x=16

-4x+44x=√16

40x=4

x=40/4

x=10