Question

solve quadratic equation 3x^-2+7x^-1+5=0​

Answer 1

Let x^-1 be y^1 then x^-2= y^2

Therefore eqn becomes

3y^2+7y^1+5 = 0

Now solve by formula to ger

Y=(-7+-underoot-11)÷6

Now put y=x^-1

U will get x=6÷(-7+-underoot-11)