solve quadratic equation (3x+4) (2x-11) = 0 solve in fraction icse students can solve
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Answer:
value of x = -4/3 And 11/2
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I am cbse one
6x2-33x+8x-44
6x2-25x-44
d=625-4×6×-44
d=625+1056
rootd=41
let two roots be alpha and beta
alpha = -6+41/12 = 35/12
Beta = -6-41/12 = -47/12
Hence, 35 /12 and -47/12 are roots of the desired quadratic eq ..
Hope it helps .
Mark it as brainlist answer .
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