Question

solve quadratic equation 5x(sq)-4x-7=0​

Answer 1

Answer:

Step-by-step explanation:

The given quadratic equation is

5x^2-4x-7=0.

Where, a=5; b=-4; c=-7

Now we have to solve this question by quadratic formula. Which is -b+-√b^2-4ac/2a.

Now putting the values in quadratic formula we get,

4+-√(-4)^2-4×(5)×(-7)/2×(5) ==>

4+-√16+140/10. ==> 4+-2√39/10.

This gives us two conditions, given below

4+2√39/10 || 4+2√39/10

2+√39/5 || 2-√30/5

So, the two roots(zeroes) of the given equation are, 2+√39/5 and 2-√39/5.

You can do it by simple factorisation also but it needs a lot of time.

I am attaching a picture so that you can understand it better.

And if my answer helped you please mark it as brainliest answer.

Thank you.

Answer 2

The answer is 2+√39/5 and 2-√39/5.

Thank you.