Question

Solve quadratic equation: 6x2-3x+5=0

Answer 1

Step-by-step explanation:

here is ur answer in the pic......

Answer 2

Quadratic equation:

Step-by-step explanation:

$\ Given \ value:\\\\6x^2-3x+5=0 \\\\\ Solution: \\\\\ formula: \\\\x= \frac{-b\±\sqrt{b^2-4ac}}{2a} \\\\\ compare \ given \ value \ ax^2+bx+ c=0 \\\\a= 6\\b= -3\\c= 5\\\ put \ the \ value \ of \ a, \ b, \ c \ in \ given \ value \\\\x= \frac{-(-3)\±\sqrt{(-3)^2-4.6.5}}{2.6} \\\\x= \frac{3\±\sqrt{9-120}}{12} \\\\x= \frac{3\±\sqrt{111}}{12} \\\\x= \frac{3 \±\ 10.53}{12}$

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