Question

solve quadratic equation briefly:2sin^2x-3sinx-2=0​

Answer 1

Explanation:

[Math Processing Error]

Replace (3sin x) by (4sin x - sin x)

f(x) = 2sin^2 x + 4sin x - sin x - 2 = 0

Factor by grouping:

f(x) = 2sin x (sin x + 2) - (sin x + 2) = 0

f(x) = (sin x + 2)(2sin x - 1) = 0

There are 2 solutions:

a. sin x = - 2 (rejected since < -1)

Answer 2

Answer:

Step-by-step explanation:

I hope you understand if you are in class 11 but if you are in class 10 then since=-1/2 is sufficient to write in exam and in high trigonometry you study 180digree in π form so check this