solve quadratic equation by completing the square 4x²-12x+9=0
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Step-by-step explanation:
Given : 4x² - 12x - 9 = 0 .
On comparing the given equation with ax² + bx + c = 0
Here, a = 4 , b = - 12 , c = - 9
D(discriminant) = b² – 4ac
D = (- 12)² - 4 × 4 × - 9
D = 144 + 144
D = 288
Since, D > 0
Therefore, root of the given equation 4x² - 12x - 9 = 0 are real and distinct.
Hence, the nature of roots of the quadratic equation 4x²− 12x − 9 = 0 are real and distinct.
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