Question

solve quadratic equation by factoring with solution
x² = 11x + 3​

Answer 1

x2 −11x+30=0

⇒x2−5x−6x+30=0

⇒x(x−5)−6(x−5)=0

⇒(x−6)(x−5)=0

So x=5,6.

HOPE THIS HELPS YOU!!!

Answer 2

✓ Answer

→ Formula :-

$x = \frac{ - b± \sqrt{ {b}^{2} - 4ac } }{2a}$

Where

$p(x) = {ax}^{2} + bx + c = 0$

${x}^{2} - 11x - 3 = 0$

Here a = 1 , b= -11 , c = -3

$x = \frac{11± \sqrt{121 - 12} }{2}$

$x = \frac{11± \sqrt{109} }{2}$

$x = \frac{11 + \sqrt{109} }{2} or \: \: \frac{11 - \sqrt{109} }{2}$

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This method is used to calculate the roots of the given polynomial equation , This method is known as quadratic method Where we use the quadratic formula.

Some equations have imaginary as its factor , To find its factor we use this formula