Question

solve quadratic equation by factorisation method 2x^2-7x-3=0​

Answer 1

Given :

Correct Question should be

$2 {x}^{2} - 7x + 3 = 0$

What to find out =Roots of the equation?

Solution :-

Factorise by splitting middle term

$2 {x}^{2} - 7x + 3 = 0 \\ 2 {x}^{2} - 6x - x + 3 = 0 \\ 2x(x - 3) - 1(x - 3) = 0 \\ (x - 3)(2x - 1) = 0$

Hence

$x_1 =3 \\ x_2 = \frac{1}{2}$

Extra information :-

• A quadratic equation is an equation of the second degree, meaning it contains at least one term that is squared. The standard form is ax² + bx + c = 0 with a, b, and c being constants, or numerical coefficients, and x is an unknown variable.

Answer 2

${\huge{\bold{\purple{\bigstar{\boxed{\boxed{\bf{Question}}}}}}}}$

$2x^2 - 7x + 3 = 0$

solve this by factorisation method

${\huge{\bold{\purple{\bigstar{\boxed{\boxed{\bf{solution}}}}}}}}$

$\sf\implies 2x^2 - 7x + 3 = 0$

$\sf\implies 2x^2 -6x -x + 3= 0$

$\sf\implies 2x(x-3) - 1(x-3) = 0$

$\sf\implies (2x-1)(x-3) = 0$

• roots in the equation

$\sf\implies 2x -1 = 0$

$\sf\implies 2x = 1$

$\sf\implies x = \dfrac{1}{2}$

__________________

$x - 3 = 0$

$x = 3$

${\bold{\blue{\boxed{\bf{\dfrac{1}{2} }}}}}$ and ${\bold{\blue{\boxed{\bf{ 3 }}}}}$

_________________❤

Thank you❤