Question

Solve quadratic equation by factorization method:
x2 + 2√2x - 6 = 0​

Answer 1

${x}^{2} + 2 \sqrt{2} x - 6 = 0$

$= > {x}^{2} + 3 \sqrt{2} x - \sqrt{2}x - 6 = 0$

$= > x(x + 3 \sqrt{2} ) - \sqrt{2} (x + 3 \sqrt{2} ) = 0$

$= > (x - \sqrt{2} )(x + 3 \sqrt{2} ) = 0$

$= > x = \sqrt{2} \: and \: x = - 3 \sqrt{2}$

Hence, this is the required answer.

Hope it helps!