Solve quadratic equation by Factorization :
![\frac{1}{2a + b + 2x} = \frac{1}{2a} + \frac{1}{b} + \frac{1}{2x} \frac{1}{2a + b + 2x} = \frac{1}{2a} + \frac{1}{b} + \frac{1}{2x}](https://tex.z-dn.net/?f=+%5Cfrac%7B1%7D%7B2a+%2B+b+%2B+2x%7D++%3D++%5Cfrac%7B1%7D%7B2a%7D++%2B++%5Cfrac%7B1%7D%7Bb%7D++%2B++%5Cfrac%7B1%7D%7B2x%7D+)
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6
hey mate here's ur answer
hope it helps u
hope it helps u
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NainaMehra:
it's wrong
Answered by
3
⇒ -ab = x(2a + b + 2x)
⇒ -ab = 2ax + bx + 2x^2
⇒ 2x^2 + 2ax + bx + ab = 0
⇒ 2x(x + a) + b(x + a) = 0
⇒ (x + a)(2x + b) = 0
⇒ x = -a, -b/2.
Hope it helps!
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