Solve quadratic equation in x by factorization method.
a2 x2 + (a2 + b2) x + b² = 0;
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Step-by-step explanation:
Given:-
a^2 x^2 + (a^2 + b^2) x + b^2= 0
To find:-
Solve quadratic equation in x by factorization method for a^2 x^2 + (a^2 + b^2) x + b^2= 0
Solution:-
Given quadratic equation is
a^2 x^2 + (a^2 + b^2) x + b^2= 0
=>a^2 x^2 + a^2 x + b^2 x + b^2= 0
=>a^2 x (x + 1) + b^2 (x + 1) = 0
=>(x + 1) (a^2 x + b^2) = 0
=>x + 1 = 0 (or) a^2 x + b^2 = 0
=>x = -1 (or) a^2 x = -b^2
=>x = -1 (or) x = -b^2/a^2
Therefore, x = -1 and -b^2/a^2
Answer:-
The values of x are -1 and -b^2/a^2
The roots of the given quadratic equation are
-1 and -b^2/a^2
Used Method:-
- Factorization method
Additional information:-
- An equation of the degree is two is called a quadratic equation.
- The standard form of a quadratic equation is ax^2+bx+c=0.
- A quadratic equation has at most two roots.
- We use factorization method,quadratic formula method (Sridharacharya method) for solving a quadratic equation.
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