Question

solve quadratic equation kx(x-2)+6=0 find the value of k

Answer 1

From the quadratic equation, the value of k is 6.

Step-by-step explanation:

Given:

Solve quadratic equation kx(x-2)+6=0 find the value of k

Solution:

$kx^2$ – 2kx + 6 = 0

Since the quadratic has equal roots, $b^2$ – 4ac = 0

$(-2k)^2$ – 4k +6 =0

K = 0 or 6

To know more:

Solve the given quadratic equation:  x² + 3ix + 10 = 0

https://brainly.in/question/7853683

Solve the following quadratic equation by factorisation m^2-14m+13=0

https://brainly.in/question/4204847

Answer 2

Answer:

kx(x-2)+6=0

Step-by-step explanation:

kx²-2kx+6=0

a=K

b=-2k

c=6

x=b²-4ac

= (-2k)²-4×k×6=0

= 4k²-24k=0

by taking 4 common ..

4k(k-6)=0

4k=0 and k-6=0

k=0/4=0 and k=0+6=6

so 0 or 6