Question

solve quadratic equation kx(x-2)+6=0 find the value of k

Answer 1

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Given kx(x – 2) + 6 = 0 kx2 – 2kx + 6 = 0 Since the given quadratic equation has equal roots  we have b2 – 4ac = 0 That is (– 2k)2 – 4(k)(6) = 0 ⇒ 4k2 – 24k = 0 ⇒ 4k(k – 6) = 0⇒ 4k = 0 or (k – 6) = 0 ∴ k = 0 or 6

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