Solve quadratic equations m2-14m+13=0 by factorisation
Answers
Answered by
10
Answer :
Step-by-step explanation :
Given quadratic equation,
m² - 14m + 13 = 0
=> It is of the form ax² + bx + c
a = 1, b = -14, c = 13
a - coefficient of x²
b - coefficient of x
c - constant term
By sum-product pattern,
>> Find the product of quadratic term [ax²] and constant term [c]
= m² × 13
= 13m²
>> find the factors of "13m²" in pairs
=> (m) (13m)
=> (-m) (-13m)
>> From the above, find the pair that adds to get linear term [bx]
- m - 13m = -14m
>> So, split -14m as -m and -13m
m² - 14m + 13 = 0
m² - m - 13m + 13 = 0
>> Find the common factor
m(m - 1) - 13(m - 1) = 0
(m - 1) (m - 13) = 0
=> (m - 1) = 0 ; m = +1
=> (m - 13) = 0 ; m = +13
The zeroes of the polynomial are 1 and 13.
Similar questions