Solve quadratic equations using formula
y²-2y=-3=0
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Answer:
Step 1 :Trying to factor by splitting the middle term. 1.1 Factoring y2-2y+3. The first term is, y2 its coefficient is 1 . The middle term is, -2y its coefficient is -2 . ...
Step 2 : Parabola, Finding the Vertex: 2.1 Find the Vertex of t = y2-2y+3.
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Solution: y=1+√5;y=1-√5
Step-by-step explanation:
y²-2y-3=0
a=1, b=-2,c=-3
b²-4ac
=-2²-4×-2×-3
=4-(-16)
=4+16
=20
Using quadratic formula
y={-b±√(b²-4ac)}/2a
y={-(-2)±√20}/2×1
y=(2±√20)/2
y=(2+√20)/2 ; y=(2-√20)/2
y=(2+2√5)/2 ; y=(2-2√5)/2
y=2(1+√5)/2 ; y=2(1-√5)/2
y=1+√5 ; y=1-√5
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