Question

Solve quaratic equations using fromula
.x^{2} + 10x +2=0

Answer 1

Answer:

x = [-10 ± 2√23] / 2

$x=\frac{-10+2\sqrt{23} }{2} \\\\x=\frac{-10-2\sqrt{23} }{2}$

Step-by-step explanation:

$x^{2} +10x+2$

Using Quadratic formula,

x = [-b ± √b² - 4ac] / 2a

x = [-10 ± √(10)² - 4(1)(2)] / 2(1)

x = [-10 ± √100 - 8] / 2

x = [-10 ± √92] / 2

x = [-10 ± 2√23] / 2

$x=\frac{-10+2\sqrt{23} }{2} \\\\x=\frac{-10-2\sqrt{23} }{2}$