SOLVE QUDRATIC EQUATION 2
+13x+15=0
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Substitution y=tan2x then we have. 2y2−y−15=0 2y2−6y+5y−15=0 2y(y−3)+5(y−3)=0 (2y+5)(y−3)=0 y=tan2x=−52;3. Proceed for solving ...
Missing: 13x+ | Must include: 13x+
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