solve QUE 4 by elimination method
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Answer:
the roots of given equation are x=2 and y=3
Step-by-step explanation
ANSWER
Let 0.2x+0.3y=1.3 ....(1)
0.4x+0.5y=2.3 ....(2)
Multiply eqn(1) by 10 we get
2x+3y=13 ....(3)
Multiply eqn(2) by 10 we get
4x+5y=23 ....(4)
Solving equations (3) and (4)
5×(3)⇒10x+15y=65
3×(4)⇒12x+15y=69
Subtracting we get 12x+15y−10x−15y=69−65=4
or 2x=4 or x=2
Substituting x=2 in eqn(3) we get
2x+3y=13⇒2×2+3y=13 or 3y=13−4=9 or y=3
Hence x=2,y=3
HOPE IT WILL HELP YOU
Answered by
1
Step-by-step explanation:
0.2x+0.3y= 1.3×0.4
0.4x+0.5y= 2.3×0.2
:0.08x+.12y= 0.52
0.08x+.10y= 0.46
:12y-10y=0.06
:2y=0.06
:y=0.03
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