Question

Solve que no 35 please

Answer 1

A= 5i and B= 5√2 cos45°i+ 5√2sin45°j = 5√2(1/√2)I+5√2(1/√2)j =5i+5j .C= 5j .A+B+C = 10i+10j Magnitude of this vector is √100+100 =10√2 . And direction is 45°N of E as in first quadrant only both are positive .