solve que no 5 and 6 its urgnt tomorrow will be my exm plz help me gys
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(5).Square Sides Measures=6 m
Area=Side²
Area=6²
Area=36 m²
Area of Square=Area Of Parallelogram
Base=18 m
Area of Parallelogram=Base×Height
Let Height=X
A/Q
18×x=36
x=36/8
x=2
Height=2 m
(6)Area Of Parallelogram ABCD=6 2/5 cm²
=32/5 cm²
Area of Parallelogram=Base ×Height
Base=8 cm
Height=xa
A/Q
8×xa=32/5
xa=32/5×1/8
xa=4/5 cm
Now Focus on Triangle DCY
We know DC will =8 cm
And DA=6 cm
As in Parallelogram opposite sides are Equal
Now We Get Triangle DCY
In which
DC=8cm (height)
DY=6cm (base)
CY=?
Now
Use Phythagoras Theroem
CY²=Base²+Height ²
CY²=8²+6²
CY²=64+36
CY²=100
CY=√100
CY=10 cm
XA=4/5 cm
CY=10 cm
Area=Side²
Area=6²
Area=36 m²
Area of Square=Area Of Parallelogram
Base=18 m
Area of Parallelogram=Base×Height
Let Height=X
A/Q
18×x=36
x=36/8
x=2
Height=2 m
(6)Area Of Parallelogram ABCD=6 2/5 cm²
=32/5 cm²
Area of Parallelogram=Base ×Height
Base=8 cm
Height=xa
A/Q
8×xa=32/5
xa=32/5×1/8
xa=4/5 cm
Now Focus on Triangle DCY
We know DC will =8 cm
And DA=6 cm
As in Parallelogram opposite sides are Equal
Now We Get Triangle DCY
In which
DC=8cm (height)
DY=6cm (base)
CY=?
Now
Use Phythagoras Theroem
CY²=Base²+Height ²
CY²=8²+6²
CY²=64+36
CY²=100
CY=√100
CY=10 cm
XA=4/5 cm
CY=10 cm
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