Question

solve ques. 14 A To be the brainliest I will really mark it as brainliest

Answer 1

Let the digit at tens place be x and the digit at units place be y.

Then the original number is 10x + y.

Given that sum of digits of a 2-digit number is 6.

= > x + y = 6    ------ (1)

Given that if 18 is added the the digits are interchanged.

= > 10x + y + 18 = 10y + x

= > 10x + y - 10y - x = -18

= > 9x - 9y = -18  

= > x - y = -2  ------- (2)

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On solving (1) & (2), we get

= > x + y = 6

= > x - y = -2

    ---------------

    2x = 4

      x = 2.

Substitute x = 2 in (1), we get

= > x + y = 6

= > 2 + y = 6

= > y = 6 - 2

= > y = 2.

Hence, the original number = 10x + y = 10(2) + 4 = 24.

Therefore, the number is 24.

Hope this helps!

Answer 2

$<b>Solution:$

Let the ten's digit be x.

Then, the one's digit = (6 - x).

Original Number

=> 10x + 6 - x

=> 9x + 6

After interchanging the numbers.

New number = 10(6 - x) + x

=> 60 - 10x + x

=> 60 - 9x

From the question,

9x + 6 + 18 = 60 - 9x

⇒9x + 24 = 60 - 9x

⇒9x + 9x = 60 - 24

⇒18x = 36

⇒x = 36/18

⇒x = 2

On putting the value of x

Original number

⇒ 9x + 6

⇒9 × 2 + 6

⇒18 + 6

⇒24

Hence , the original number is 24.


Thanks for the question!